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Write the trigonometric expression in terms of sine and cosine, and then simplify. (1 + tan^2 θ) cos^2 θ
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\[\left(\frac{\cos^2\theta}{\cos^2\theta} + \frac{\sin^2\theta}{\cos^2 \theta}\right)\cos^2\theta\]
\[\left(\frac{\cos^2\theta + \sin^2\theta}{\cos^2\theta} \right)\cos^2\theta\]
common denominator right?
\[\left(\frac{\cos^2\theta + \sin^2\theta}{\cancel{\cos^2\theta}} \right)\cancel{\cos^2\theta}\]
oic, so will i use the reciprocal identity tan x = sin x/cos x
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\[=\cos^2 \theta + \sin^2 \theta \\=1\]
neat thanks for your time
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