Ask your own question, for FREE!
Mathematics 8 Online
OpenStudy (anonymous):

What is the solution set of {x | x < -3} ∩ {x | x > 5}?

OpenStudy (anonymous):

and can u explain it?

OpenStudy (anonymous):

@tomiko

OpenStudy (anonymous):

first find the solution set of {x | x < -3}. what will this be?

OpenStudy (anonymous):

then find for {x | x > 5}. ok? then we can find the intersection of this sets.

OpenStudy (anonymous):

UMM, -2,-1,0,1,2,3,4,5,6,7,8...exc..

OpenStudy (anonymous):

6!?

OpenStudy (anonymous):

wrong in both questions. what are the values such that x < -3?

OpenStudy (anonymous):

that's for the fist part

OpenStudy (anonymous):

i dont know?

OpenStudy (anonymous):

they are -4, -5, -6, -7, ..... to infinity. do you get it? that's for the first part. now how about the second part?

OpenStudy (anonymous):

-4,-3,-2....?

OpenStudy (anonymous):

no. for x such that x > 5 will be 6, 7, 8, 9, 10 and so on.

OpenStudy (anonymous):

do you get it?

OpenStudy (anonymous):

no not really..

OpenStudy (anonymous):

x | x > 5 means values of x that are GREATER than 5. 6 is greater than 5. so is 7 and 8 and 9 and above. that's all it means. the first one x | x < -3, means values of x that are less than -3. now, -4 is less than -3...so is -4 and -5 and so on. got it now?

OpenStudy (anonymous):

oh yeah, so what would be the answer?

OpenStudy (anonymous):

what do YOU think then answer will be now? what is the intersection of these 2 sets? can you please try?

OpenStudy (anonymous):

the numbers exept -3 and 5

OpenStudy (anonymous):

no. the solution set is an EMPTY set....

OpenStudy (anonymous):

why?

OpenStudy (anonymous):

thank you for putting up with me btw.

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!