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find the i and j component of v in terms of the magnitude of v ad theta simplifying your answer (theta is in the second quadrant )
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can somebody hlp me please
|dw:1354103141379:dw|
i = v*cos(180-theta) j = v*sin(180-theta)
Thanks a lot that's what I got but couldn't simplify it much more
great! It's already simplified. Note that in order to obtain vector components, let's say along the x-axis or i, you have to start at 0 degrees. but since the given angle theta is at the second quadrant, I subtracted 180 to theta to get the angle starting from zero. |dw:1354103926633:dw| with that, we can say that: i = v*cos(180-theta) = v*cos(alpha) j = v*sin(180-theta) = v*sin(alpha)
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