Question

4x^2+32x-(-48)=0

Helppppp

Answer 1

4x^2+32x-(-48)=0
negative and negative gives you positive
4x^2+32x+48=0
Solve it like a quadratic equation

Answer 2

how do you do 4(x+6)(x+2) ?
do you distribute the 4 to both x+6 and x+2 or just x+6?

Answer 3

both of them since you factorize out from both. One way to check is to multiply the 4 back into brackets and see if you get back your original equation

Answer 4

when i did it i only got \[4x ^{2}+32\]

Answer 5

i didnt end up with the -(-48)

Answer 6

How did you get 4x^2+32?

Answer 7

4(x+6)(x+2)

Answer 8

unless I'm doing it wrong

Answer 9

you multiply the four into the first bracket
4x+24(x+2)

Multiply each term with both the terms inside bracket
4x*x+4x*2+24*x+24*2
=4x^2+8x+24x+48
=4x^2 +32x + 48
=4x^2 + 32x -(-48)

Answer 10

ohhhhhh okay , i see!

Answer 11

another question , if you dont mind