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Find the sum of the first 12 terms of the sequence. Show all work for full credit. 1, -4, -9, -14, . . .
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this is arithmetic sequence, the sum of the n first term is \[Sn = \frac{ n }{ 2 }\left( 2a + \left( n-1 \right) d \right)\] with n = the number of terms a = the first term d = the difference you can use this formula to solve the problem can you determine, what is n, a, and d of your sequence?
d=-9-(-4) =-9+4 =-5 n=12 a=1.
yess... :) now, plug in the value into the formula...
12/2(2*1+(12-1)-5)
which equals 48?
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be careful in calculation.... :)|dw:1354117455248:dw|
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