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How do you simplify 12^log sub 12 base 144?
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\[12^{\log _{12}144}\]
Hint: \[\Large b^{\log_b(x)} = x\]
so the answer is 144?
what about for \[9^{\log _{3}20}\]
i know u can get it to \[3^{2^{\log _{3}20}}\]
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but then what?
yes the answer to the first one is 144
do you know about the second
\[\Large 9^{\log_{3}(20)}\] \[\Large (3^2)^{\log_{3}(20)}\] \[\Large 3^{2\log_{3}(20)}\] \[\Large 3^{\log_{3}(20^2)}\]
so once you get the base of 3 you kind of do a reverse power property? so the answer is 400?
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yep
thanks!!!
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