Question

double integral 3x^2-3y^2 dydx on circle x^2+y^2=4 how do i find the endpoints using the circle.

Answer 1

convert to polar coordinates.
\[x=r*\cos(\theta); y=r*sin(\theta)\]
\[F(x,y)=F(r,\theta)=3r^2cos^2(\theta)-3r^2sin^2(\theta)\]
your limits of integration would be \[r=[0,2]; \theta=[0.2\pi]\]
the integral would then become \[\int\limits_{0}^{2\pi}\int\limits_{0}^{2}r*F(r,\theta)drd\theta\]

Answer 2

end points of r?

Answer 3

i meant the limit?