Question

Please help!

What is the remainder of (x^3–6x–9x+3)÷(x-3) ?

A. -51

B. -51/x - 3

C. -17/x

D. -17/x - 3

A, B, C, or D? Please explain (:

Answer 1

We lost you, last time. Did we agree that it would look like this: \(\dfrac{something}{x-3}\)?

Answer 2

Is the second term actually -6x² ?

Answer 3

BTW "-51/x-3" means \(\dfrac{-51}{x} - 3\)

If you want \(\dfrac{-51}{x-3}\), you must use parentheses. "-51/(x-3)"

Order of operations and all.

Answer 4

@SueSt.John

If the second term is -6x² then A. -51 is the remainder.

Answer 5

Yes, I agree. The remainder is -51. The fourth term in the quotient would be -51/(x-3)

Answer 6

http://openstudy.com/study#/updates/50b6fd91e4b07527f06b2cd9