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Linear Algebra
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what is -x+y=5 in y=mx+b form?
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just add the x to both sides y=x+5
do you know how that equation will be if it was perpendicular?
Perpendicular to what?
perpendicular to a line that has an equation of -x+y=5
and passes through points (2,-5)
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You want the equation of a line that is perpendicular to -x+y=5 and that passes through the point (2,-5)?
yes please
Well since we put -x+y=5 into y=mx+b form y=x+5 we can see the slope is 1. a line perpendicular to that would have a slope of -1. So use that and your point to find the equation. y+5=-1(x-2) simplify that
would it be the same if it were solving for a parallel line?
No, parallel lines have the same slope.
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thank you :)
You're welcome
solve for y
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