Question

how do you solve this equation using factoring x2+13x+40=0

Answer 1

Solve using the quadratic equation: \[x=\frac{ -b \pm \sqrt{b^{2}-4ac} }{ 2a }\]
x^2+13x+40 = 0
a=1, b=13, c=40

Answer 2

Or by factoring:
What are 2 factors (2 numbers that you multiply that will give you 40) of 40 (a*c=1*40=40) and when you add them together you get 13 (b).
Can you find those factors?

Answer 3

Are u there?

Answer 4

yea thanks man im in algebra 2 class and these problems are killing me

Answer 5

What are the factors of 40 2 numbers that you multiply that will give you 40?
1. 40 and 1
2. 2 and 20
Can you find the others?

Answer 6

x^2+8x+5x+40
x^2+13x+40