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OpenStudy (anonymous):
I am having problems trying to figure out how to solve radical expressions theproblem is 3(checkmarkthing) x-2=3
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OpenStudy (anonymous):
|dw:1354386090014:dw|
OpenStudy (anonymous):
Don't you solve for x?
OpenStudy (anonymous):
yes but i cant figure out how to get x alone im lookint at my book and i dont understand it
OpenStudy (anonymous):
ah ok, well you know your order of operations right?
when you are simplifying, all you do is instead of PEMDAS you SADMEP
OpenStudy (anonymous):
so add/subtract from the x side, then multiply/divide
then square both sides
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OpenStudy (anonymous):
|dw:1354386419159:dw|
OpenStudy (anonymous):
erm, no 3(sqrtx)-2=3
+2 +2
3(sqrt x)=5
/3 /3
(sqrt x)=5/3
and in order to get rid of a square root you square it so ou would get
(-/x)^2=(5/3)^2
OpenStudy (anonymous):
is it
\[3\sqrt{x-2}=3\] or is it
\[3\sqrt{x}-2=3\]?
OpenStudy (anonymous):
I think the second one, juding by the pic at the top
OpenStudy (anonymous):
firstone
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OpenStudy (anonymous):
oh ok then,
the you get 3(sqrt x-2)=2
/3 /3
OpenStudy (anonymous):
and square both sides
OpenStudy (anonymous):
then add 2
OpenStudy (anonymous):
then divide both sides by 3 and get
\[\sqrt{x-2}=1\] square both sides and get
\[x-2=1\] therefor \(x=3\)
OpenStudy (anonymous):
^3sqrt x-2=3
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