how do I find all the solutions in this equation? csc(θ/2) =sin (θ/2)
The solutions to the equation occur whenever csc(θ/2) =sin (θ/2). In other words, just graph it and observe visually
where both intersect each other
we dont solve the questions graphing them...do you have another method to solve it?
csc (theta/2) = sin (theta/2) 1/sin(theta/2) = sin (theta/2) 1 = sin^2(theta/2) solve for theta + k2pi where k is an element of an integer
srry 4pi not 2pi
one is the reciprocal of the other, so imagine you were trying to solve \(x=\frac{1}{x}\) what would you get ?
hopefully you get \(x=1\) or \(x=-1\) telling you \(\sin(\frac{\theta}{2})=1\) or \(\sin(\frac{\theta}{2})=-1\)
yeah, I got -1 or 1
on the interval \([0,2\pi)\) the occurs at two places, \(\frac{\theta}{2}=\frac{\pi}{2}\) or \(\frac{\theta}{2}=\frac{3\pi}{2}\)
solving for \(\theta\) we get \(\theta=\pi\) or \(\theta=3\pi\)
if you are looking for some general solution, it is an odd integer times \(\pi\) which you could write at \(\theta=(2k+1)\pi, k\in \mathbb{Z}\)
ok, thanks! I got it right! :)
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