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e^-x sinx
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\[y = e^{-x} \sin x \] right? if so...I got\[\frac{dy}{dx} = \frac{\cos x - \sin x}{e^x}\]
sometimes I use the chain rule incorrectly, this is one of those times ok so now what?
find the critical points by setting y' = 0 and solving for x
how come the derivative of sin(x) is not equal to cos(x)?
so cosx - sinx = 0 ?
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it is! in this problem you must use the product rule
cos x = sin x what value of x makes the statement true?
ahhh ok product rule um -1 ?
Pi/4! cos pi/4 = sin pi/4
how do you get Pi/4?
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|dw:1354479386799:dw|
ahhhhh
=D
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