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OpenStudy (anonymous):
Solve. 2x2 = 8
x = 2
x = 2 and x = –2
x = –2 and x = 4
x = 4
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OpenStudy (anonymous):
do you mean
\[2x ^{2}=8\]
OpenStudy (anonymous):
x=+,-2
OpenStudy (anonymous):
yes im sorry @MathDad72
OpenStudy (anonymous):
that's ok you want to go through the steps to solve? or just use the answers given?
OpenStudy (anonymous):
if you could just explain how you got your answer that would be great
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OpenStudy (anonymous):
We want to get the x by itself, correct?
OpenStudy (anonymous):
correct!
OpenStudy (anonymous):
how would you "move" the 2 over to the other side?
OpenStudy (anonymous):
\[(\frac{ 1 }{ 2 }) 2x ^{2} = 8(\frac{ 1 }{ 2 })\]
Does this make sense?
OpenStudy (anonymous):
divide?
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OpenStudy (anonymous):
correct
if you divide the left side by 2 you will get
\[x ^{2}\]
OpenStudy (anonymous):
and
what ever you do to one side you need to do to the other (right)
\[x ^{2} = 4\]
OpenStudy (anonymous):
still good?
OpenStudy (anonymous):
so now to "move" the square to the other side.
OpenStudy (anonymous):
\[\sqrt{x ^{2}} = \pm \sqrt{4}\]
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OpenStudy (anonymous):
\[x = \pm 2\]
OpenStudy (anonymous):
Anything you want to go over in more detail? Or are you good?
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