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y=sec ^3 x/2
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\[y=\sec^{3}\frac{x}{2}\]
\[\frac{dy}{dx}=3\sec^{2}\frac{x}{2} \sec \frac {x}{2} \tan \frac{x}{2}\]
is that correct @sirm3d
One more link in the chain is needed...d/dx(x/2)=1/2 Tack that on.
so everything into half?
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i dont think so http://www.wolframalpha.com/input/?i=derivative+of+y%3Dsec%5E3+x%2F2
Yes... in a sense, since it is all multiplied... but it will only change that 3 in front to 3/2
oh its there sorry
:P
No problem. And wolfram combined the secants.
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I did too
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