Question

Derivative help

Answer 1

\[\large y=e^{\sqrt x}(\log(cosx))\]

Answer 2

\[e^{\sqrt x} (\log(\cos x)) \times \frac{1}{2 \sqrt{x}} \times \frac{1}{cosx} \times - sinx\]

Answer 3

yes thats DE?

Answer 4

we are finding the derivative

Answer 5

hmm it's not DE.. in DE mostly the question is a derivative and u basically have to integrate or what so ever other methods u have to apply according to question

Answer 6

thanks,sorry

Answer 7

lol

Answer 8

lol

Answer 9

Lets get back to your question :)

Answer 10

i think theres a e^sqrt x missing with tanx,not sure..thats in the solution..buthow

Answer 11

http://www.wolframalpha.com/input/?i=e%5E(sqrt%20x)(log(cosx))&t=crmtb01

Answer 12

there are two factors, e^{sqrt x} and log {cos x}, so use the product rule
also each factor is a chain, so chain rule apply to the two factors.

Answer 13

it just got complex e.e

Answer 14

yeah. it's chain rule and product rule in one problem.

Answer 15

let's put \[\large u=e^\sqrt x; \space v= \log (\cos x)\] and compute u' and v' by chain rule.

Answer 16

\[\large u \prime=e^\sqrt x \left( \frac{ 1 }{ 2\sqrt x } \right)=\frac{ e^\sqrt x }{ 2\sqrt x }\]\[\large v \prime =\frac{-\sin x }{ \cos x }=-\tan x\] just sub u, u', v and v' in the formula \[\large y \prime = D(uv)=u \prime v +v \prime u\]

Answer 17

why didn't we solve log(cosx) with UV method?