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I need help setting up my limits of integration for the double integral: ∫ ∫ y^3 where D is bound by the triangle with vertices at 0,2 1,1 and 3,2
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|dw:1354568371743:dw| we'll use a horizontal strip to set up the double integral
oh...so we need to get the eq of both lines correct? and then integrate over y = 1 to 3? and use the equations for the line as limits for x
first we scan the strip left to right. that would be dx. Then well scan the triangle bottom to top using the strip, and that would be dy.
y=1 to 2 only. and you are right, use the lines as the limits for x.
oh, yes, 1 to 2.
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Thank you that is what I needed to "see"
welcome. ^^
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