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Physics 13 Online
OpenStudy (anonymous):

two particles P an Q move on a line of greatest slope of a smooth inclined plane. the particles start at the same instant and from the same point, each with speed 1.3 m/s. initially P moves down the plane and Q moves up the plane. the distance between the particles t seconds after they start to move is d metres. 1. show that d= 2.6t when t=2.5 the difference in the vertical height of the particles is 1.6m. find: 2. the acceleration of the particles down the plane, 3. the distance travelled by P when Q is at its highest point.

OpenStudy (anonymous):

this can be done by applying maths. you just need to use this physical concept: v=s/t do you need further help?

OpenStudy (vincent-lyon.fr):

What is the angle of the plane to the horizontal?

OpenStudy (anonymous):

the angle is not given

OpenStudy (anonymous):

note that it's speed. the angle isn't really need. basically it's |dw:1354616449530:dw|

OpenStudy (anonymous):

speed of approach * e = speed of separation?

OpenStudy (anonymous):

but what is meant by greatest slope?

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