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Mathematics 17 Online
OpenStudy (anonymous):

find f'(x) for f(x)=xe^2x

OpenStudy (nubeer):

you have to differentiate with the help of product rule.

OpenStudy (anonymous):

so it will be something like \[xe ^{2x}(2)\]

OpenStudy (nubeer):

yes its one part of derivative.. it's still incomplete uv'+vu' you have just found uv'

OpenStudy (anonymous):

x(e^2x(2)+e^2x(1)

OpenStudy (nubeer):

yup looks right now.

OpenStudy (anonymous):

ok. thanks

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