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. Are the graphs of 2y = -3x + 6 and y = 2/3 x + 2, parallel, Perpendicular, or neither? How do you know?
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Since the second equation is already in y = mx + b form, solve the first equation for y to get it in the same form
?
I dont know :/
2y = -3x + 6 Divide both sides by 2: y = (-3/2)x + 3 What multiplies x on the right side is the slope. If the two numbers multiplying x are equal and the other numbers (b) different, the lines are parallel. Here you have 2/3 and -3/2. They're not equal. If the two values of m are negative reciprocals, then the lines are perpendicular. Negative reciprocals are numbers that when multiplied together the product is -1.
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