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Mathematics 16 Online
OpenStudy (anonymous):

Solve: 35/X^2=4x+15

OpenStudy (anonymous):

Multiply the first with x^2 on both sides You get: 4x^3 +15x^2 = 35 Then make a substitution t = x^2, where t>0 and move over 35 You get: 4t ^ 2 +15 t-35 = 0 There you have a quadratic equation that you can solve, but since t = x^2, you get complex roots ...

OpenStudy (anonymous):

What do you mean by substuitute? I get the 4x^3 but how do you make it a quadratic?

OpenStudy (anonymous):

By putting something = x ^ 2, you can simplify your calculation, but do not forget to replace your income in your variable at the end... By example sett t = x^2, you get: 4t^2 +15t-35 = 0 Now solve the equation in the same as if t would be x When you know what t is, you know what x ^ 2 is because t = x ^ 2

OpenStudy (anonymous):

Thank you!

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