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Mathematics 9 Online
OpenStudy (anonymous):

simplify: n!/(n+1)!

OpenStudy (tamtoan):

(n+1)! = ?

OpenStudy (anonymous):

What do you mean? I wasn't given the term

OpenStudy (tamtoan):

3! = 3.2.1 right? so what's (n+1)! = ?

OpenStudy (anonymous):

n! + 1?

OpenStudy (tamtoan):

no, try this, how about n! = ?

OpenStudy (anonymous):

n+(n-1)+(n-2)+(n-3)...

OpenStudy (anonymous):

oh so is it n!+n?

OpenStudy (tamtoan):

man, that was totally wrong, you sure you already study factorial ?

OpenStudy (anonymous):

yeah haha

OpenStudy (tamtoan):

n! = n.(n-1).(n-2)....2.1 ....like 3! = 3.2.1 and 4! = 4.3.2.1 and so on...so if you can write out ...(n+1)! = ? then you can see solution easily

OpenStudy (anonymous):

oh i meant n*(n-1)*(n-2)*(n-3)...*1

OpenStudy (anonymous):

maybe you but i can't

OpenStudy (tamtoan):

look at this ...3!= 3.2.1 , 4!= 4.3.2.1 imagine your n is 3 and your n+1 is 4 ...see the relation ?

OpenStudy (anonymous):

yeah.. i would write that as (n+1)! i still don't get how to simplify it

OpenStudy (anonymous):

i thought n!+n

OpenStudy (tamtoan):

look at this again .: |dw:1354660981459:dw| see it now ?

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