Question

Solve x2 + 4x + 8 = 0

Answer 1

You have to use the quadratic equation, do you know it?

Answer 2

no

Answer 3

\[x=\frac{ -b \pm \sqrt{b^2-4ac} }{ 2a }\]

Answer 4

ax2+bx+c=0

Formula: (-b+-sqrt(b squared -4*a*c))/2a

Answer 5

so?

Answer 6

a=1, b=4, c=8, plug 'em in

Answer 7

x equals negative 2 plus or minus 4 I?

Answer 8

BluFoot?

Answer 9

+- stands for two possible resoults, both are correct

Answer 10

\[ax^2 + bx + c = 0\]\[x^2 + 4x + 8 = 0\]a = 1
b = 4
c = 8 \[x=\frac{ -b \pm \sqrt{b^2-4ac} }{ 2a } \] As BluFoot mentioned, just plug them in.\[x=\frac{ -(4) \pm \sqrt{(4)^2-4(1)(8)} }{ 2(1) } \]

Answer 11

Now lets simplify that a bit.
\[x=\frac{ -(4) \pm \sqrt{(4)^2-4(1)(8)} }{ 2(1)} \]
\[x=\frac{ -(4) \pm \sqrt{16-32} }{ 2 }\]

Answer 12

x equals negative 4 plus or minus 4 I?

Answer 13

jazy?