Question

If I am given the functions:
tanx = root3/3
and cosx = -root3/2

how do i find sinx ?

Answer 1

\[\tan =\frac{ \sin }{ \cos } (=) \sin x=\cos x \tan x (=) \sin x = -\frac{ \sqrt{3} }{ 2 } \times \frac{\sqrt{3} }{ 3 } \]
\[\sin x = -\frac{ \sqrt{3}^{2} }{ 6 } (=) sinx =- \frac{ 3 }{ 6 } (=) \sin x =-\frac{ 1 }{ 2 }\]

Answer 2

wow that made complete sense

if i i wanted to look for cosecant, it would be -2/1 ? is this correct?

Answer 3

give me a sec, it been a while since i worked with cosec

Answer 4

sure!

Answer 5

yes that is correct since \[cosec = \frac{ 1 }{ \sin x }\]

Answer 6

Thank you!