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Mathematics 14 Online
OpenStudy (anonymous):

A home cooking equipment supply company employs 7 sales representatives and 6 product designers. How many ways can this company select 4 of these employees to send to a product demonstration convention in Oahu if at least 3 product designers must attend?

OpenStudy (anonymous):

6C3 x 7 + 6C4 There are 2 terms because a sales rep may or may not be picked.

OpenStudy (anonymous):

What would be the final answer to this then? How would I set it up? Like 6!/3!(6-3)! ...

OpenStudy (anonymous):

What is your understanding of combinatorial notation? Hasn't your teacher covered this?

OpenStudy (anonymous):

No this is the homework before the actual class, so we try the work as homework before we go to class then the teacher explains to us

OpenStudy (anonymous):

6C3 is 6 combination 3. That is 6! divided by (3! x 3!)

OpenStudy (anonymous):

Yea that's what I posted above... But I didnt understand the x 7 portion you had

OpenStudy (anonymous):

It ends up being 6 x 5 x 4 X 3 x 2 x 1 divided by (3 x 2 x 1 x 3 x 2 x 1) The 7 comes into play because any one of 7 sales reps can be chosen.

OpenStudy (anonymous):

If everyone chosen is a product designer, then you have 6C4 So, you just add the two terms.

OpenStudy (anonymous):

Ok. So you really dont need the 7 in a sense? You just want to add the two terms together?

OpenStudy (anonymous):

You need the 7

OpenStudy (anonymous):

I dont understand where to put the 7. I added the two terms together and got 95

OpenStudy (anonymous):

How is it you don't understand? My first post tells you to multiply 6C3 by 7 and then add 6C4 to that product.

OpenStudy (anonymous):

I think I got it now. I just didnt know if you meant multiply the whole thing by 7 or what. Thank you

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