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Develop the function g(x) = sin(x)/x using Taylor series centered at 0
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|dw:1354672825257:dw|
How would you demonstrate that the limit x->0 of sin(x)/x = 1 using the above series?
u can expand the series, it's 1-x^2/3! +x^4/5!-x^6/7! ....., replace x by 0, then only 1 left
Thanks! and lastly, how many terms of the series minimum do you need to integrate to calculate the integral |dw:1354673904712:dw| with at least 3 decimals of precision?
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