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If cos x = cot x. then what is csc x?
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Thats what the question asked
cscx=1
Thanks Neba.zi. Can we do one more?
Of course go on!!!
if \(\cos(x)=\cot(x)\) then \[\cos(x)=\frac{\cos(x)}{\sin(x)}\] and so \[\cos(x)\sin(x)=\cos(x)\] \[\cos(x)\sin(x)-\cos(x)=0\] \[\cos(x)(\sin(x)-1)=0\] \[cos(x)=0\implies x=\frac{\pi}{2}\] \[\sin(x)=1\implies x=\frac{\pi}{2}\]
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ok. if (sin x cot x) = 1. What is cos x?
Thanks Satellite
cosx=1
cotx=cosx/sinx;sinx*cotx=(sinx)(cosx/sinx) cancel out sinx u left with cosx=1
Thanks a lot ^-^
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