OpenStudy (anonymous):

If cos x = cot x. then what is csc x?

4 years ago
OpenStudy (anonymous):

Thats what the question asked

4 years ago
OpenStudy (anonymous):

cscx=1

4 years ago
OpenStudy (anonymous):

Thanks Neba.zi. Can we do one more?

4 years ago
OpenStudy (anonymous):

Of course go on!!!

4 years ago
OpenStudy (anonymous):

if \(\cos(x)=\cot(x)\) then \[\cos(x)=\frac{\cos(x)}{\sin(x)}\] and so \[\cos(x)\sin(x)=\cos(x)\] \[\cos(x)\sin(x)-\cos(x)=0\] \[\cos(x)(\sin(x)-1)=0\] \[cos(x)=0\implies x=\frac{\pi}{2}\] \[\sin(x)=1\implies x=\frac{\pi}{2}\]

4 years ago
OpenStudy (anonymous):

ok. if (sin x cot x) = 1. What is cos x?

4 years ago
OpenStudy (anonymous):

Thanks Satellite

4 years ago
OpenStudy (anonymous):

cosx=1

4 years ago
OpenStudy (anonymous):

cotx=cosx/sinx;sinx*cotx=(sinx)(cosx/sinx) cancel out sinx u left with cosx=1

4 years ago
OpenStudy (anonymous):

Thanks a lot ^-^

4 years ago