QUADRATIC EQUATION HELP!
-Z^2=-2Z-35
I know how to put them in the formulat x=-b+-[b2-4ac/2a

the problem is after i do about 2 step into it i get completely lost. (stupid variable) z confuses me. please help!

Question

QUADRATIC EQUATION HELP!
-Z^2=-2Z-35
I know how to put them in the formulat x=-b+-[b2-4ac/2a

the problem is after i do about 2 step into it i get completely lost. (stupid variable) z confuses me. please help!

anonymous · Answer

$$-z^2=-2z-35$$

anonymous · Answer

quadratic formula

amistre64 · Answer

change z to x; the variable really doesnt care what it looks like :)

amistre64 · Answer

$$-x^2=-2x-35$$
now put it into the proper format; get it all to one side
$$0=x^2-2x-35$$
now you can easily see your abc stuff

anonymous · Answer

ok. so this is what i have x=-(-2)+-$$_(-2)-+\sqrt{(-2)^{2}-4z(140)}/2x$$

anonymous · Answer

$$x=2+-\sqrt{9-4x(140}/2x$$

anonymous · Answer

wait i have something wrong. its -4 not 9

amistre64 · Answer

there are no "variables" in the quad formula, they all get filled in by the proper coefficients

$$\frac{(-2)\pm\sqrt{(-2)^{2}-4(1)(35)}}{2(1)}$$

anonymous · Answer

oooohhhhhhh ok! now i get it! i know how to do the rest! thank you!

amistre64 · Answer

:)  good luck

anonymous · Answer

one question though

anonymous · Answer

wouldnt the 35 be negative?

amistre64 · Answer

it would, and i also missed the negative sign on the "b" in front.  good eye

anonymous · Answer

yes. either way. i know what i amo doing now. =) i appreciate the help! thanks a lot!

amistre64 · Answer

yw