Write the slope-intercept equation of the line perpendicular to y = 5/2 x - 2, which passes through the point (0, 2).
A. y = 5x + 2
B. y = -2/5x + 2
C. y = 2x + 5
D. y = 1/2x + 5
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OpenStudy (anonymous):
do you know slope intercept formula?
first of all
OpenStudy (anonymous):
nope
OpenStudy (anonymous):
are you familiar with
x axis
y axis
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
cools
lets start from there
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OpenStudy (anonymous):
okay
OpenStudy (anonymous):
do you know what a
slope (non math)
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
:)
OpenStudy (anonymous):
isnt the slope formula y=mx+b? or is it y1+y2=.....cant remeber
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OpenStudy (anonymous):
ok
slope intercept formula is
y = m x + b
y = y value
x = x value
m = slope
OpenStudy (anonymous):
oh
OpenStudy (anonymous):
o ya i fogot
b = y intercept (ill get to that later)
what slope is
rise (change or y)
y = ------------------- ( x )
run (change of x)
OpenStudy (anonymous):
okay
OpenStudy (anonymous):
|dw:1354733828607:dw|
not to scale
rise 2
--- (x )
run 1
in fraction form
2
-- = 2
1
y = 2x
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OpenStudy (anonymous):
good so far?
OpenStudy (anonymous):
yep followin yuh like ah trail:)
OpenStudy (anonymous):
now
standard slope intercept form
y = mx + b
i left out
b = y intercept
i left out in the beginning i am going back to in now
if i put
y = 2x + 3
the I draw just starts from 3