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ABCD is a rhombus. Explain why...
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The info you give, the two congruent triangles, is not enough to prove ABCD is a rhombus. It's enough to prove it's a parallelogram.
You mean the given info is that ABCD is a rhombus and you want to know why you know those 2 triangles are congruent?
Yes, please.
Ok, since ABCD is a rhombus, opposite sides are congruent.
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That means side AB is congr to side DC and side AD is congr to side BC. All of that is from the definition of a rhombus which is also a parallelogram.
Side AC is congruent to itself.
So you have three sides of one triangle, ABC which are congruent to three sides of another triangle, so the triangles are congruent by SSS.
Oh okay, this makes sense. Thank you for for helping me with this!
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