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Physics 15 Online
OpenStudy (anonymous):

a man running on a straight path at 3 meters per second accelerates uniformly to a speed of 5.23 meters per second in 9.65 seconds. What is the total distance traveled? What formula can i use?

OpenStudy (anonymous):

\[x _{f}=x _{i}+v _{1}\Delta t+\frac{ 1 }{ 2 }a \Delta t ^{2}\]

OpenStudy (anonymous):

whats a?

OpenStudy (anonymous):

a would be the acceleration.

OpenStudy (anonymous):

what would it be in this case though? like what number?

OpenStudy (anonymous):

Actually the first equation you should use is this one \[v _{f}=v _{i}+a \Delta t\]

OpenStudy (anonymous):

this will help you compute your acceleration.

OpenStudy (anonymous):

ohh so first we solve for acceleration and then plug it into the other formula?

OpenStudy (anonymous):

then you could actually just use the formula \[v _{f}^{2}=v _{i}^{2}+2a \Delta x\] and compute the total distance.

OpenStudy (anonymous):

so you actually won't even need the first formula, so you can disregard it.

OpenStudy (anonymous):

what did u end up getting for acceleration because i got 4 and then did the problem and got it wrong..

OpenStudy (anonymous):

the answer is not 4.

OpenStudy (anonymous):

just kidding!

OpenStudy (anonymous):

i got it! haha i divided wrong

OpenStudy (anonymous):

you should setup the problem and show me how you did it. but the answer came out to be 39.7

OpenStudy (anonymous):

ok good job :)

OpenStudy (anonymous):

lol yeah i figured it out haha i have some more questions and i dont know what formulas to use and i have my test tomorrow, would u mind helping me out?

OpenStudy (anonymous):

i dont mind reposting it so i could give u the best answer but would u mind helping me?

OpenStudy (anonymous):

sure. could you make a new thread for it though? This one is cluttered now.

OpenStudy (anonymous):

yes! no problem! gracias

OpenStudy (anonymous):

de nada

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