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Mathematics 13 Online
OpenStudy (anonymous):

Which of the following coordinates is nearest to the right of the origin on a coordinate plane? A) (-3, 0) B) (5, 0) C) (2, 1) D) (4, 4)

OpenStudy (anonymous):

Hi need help i think it is 5,0

OpenStudy (anonymous):

No wait 4,4

OpenStudy (anonymous):

the origin is (0,0)

OpenStudy (anonymous):

If you can can you help me on other problems to

OpenStudy (anonymous):

not to gve me the asnwer but help me correct them???

OpenStudy (anonymous):

so you want x to be positive and y to be close to 0

OpenStudy (anonymous):

Well i am guessing whatever of the sets that are listed above is closiest to the right!

OpenStudy (anonymous):

Hey

OpenStudy (anonymous):

Mark o can you help me please reply O:

OpenStudy (anonymous):

i just told you what to do, guessing doesnt get you anywhere

OpenStudy (anonymous):

use the distant to a point formula to know which one is closer or less distance to the origin (0,0) the distance formula is \[d=\sqrt{(x1-x2)^{2}+(y1-y2)^{2}}\]

OpenStudy (anonymous):

solve them all against the origin (0,0) for A) (-3, 0)=(x1,y1).., (0,0)=(x2,y2) \[d=\sqrt{(-3-0)^{2}+(0-0)^{2}}= \]

OpenStudy (anonymous):

solve them from A to D and compare which one is the nearest to the right of the origin (0,0)

OpenStudy (anonymous):

@ Need_Help_Correcting

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