Question

6x^2+10xy-4y^2, i have to factor this completely, help please!!!

Answer 1

Hello.

First let's factor out a 2 since all the coefficients are even. Then we have \[2(3x ^{2}+5xy-2y ^{2})\]
Now since it is a quadratic expression it will have 2 factors, one of form (a+b) and one of form (c-d) (this is because of the signs; since the first sign is positive that is the sign in the first set of parenthesis, and since the second sign is negative we take the opposite of the first sign, in this case it becomes negative).

We also know that a and c will be some coefficient times x, while b and d will be some coefficient times y. a*c must equal 3x^2 and b*d must equal 2y^2. Also, a*d+b*c must equal 5xy.

Let's try a=x and c=3x (since ac=3x^2 now). Can you do the rest?

Answer 2

if i dont input it the way the computer wants it then it counts it wrong. i only have a little to go off of, but i have to set i up like _(3+_____________ if i could set it up as 2(3x^2+5xy-2y^2) then i would have been able to do the problem