Verify the basic identity. What is the domain of validity?
cotθ = cosθ cscθ
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OpenStudy (anonymous):
Are you trying to prove the identity?
OpenStudy (anonymous):
Yes and Domain of validity?
OpenStudy (anonymous):
cotx=cosxcscx
Replace cscx with an equivalent expression (1)/(sin(x)) using the fundamental identities.
(cosx)/(sin(x))
Rewrite the expression using the (cosx)/(sinx)=cotx identity.
OpenStudy (anonymous):
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OpenStudy (anonymous):
thats the answer
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OpenStudy (anonymous):
To prove the identity yes. I just don't understand what you mean by domain of validity.
OpenStudy (anonymous):
whaT YOU THINK IT Can be ?
OpenStudy (anonymous):
This is for trig, correct?
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
I've never heard of domain of validity. Perhaps the question is asking what the domain is??
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OpenStudy (anonymous):
it said Domain of validity
OpenStudy (anonymous):
Every pi interval then. so:
0< theta-pi (n)<pi.
OpenStudy (anonymous):
so im PUT THAT AS ANSWER
OpenStudy (anonymous):
It should be correct.
OpenStudy (anonymous):
THANKS MAN . I MIGHT NEED SOME HELP. CAN I MESSAGE IF I NEED MORE HELP
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