Question

find the equation of the tangent line to f(x)=2x^2, @ x=1

Answer 1

take the derivative of f(x), then substitute in x=1. then (1,f(1)) is your point and your f'(1) is your slope.

what i mean is....
f'I(x) = 4x
f'(1) = 4
(1,4) m = 4
Use point-slope form to find the equation.
I think I'm right?

Answer 2

so do i just ignore the x and call m the slope?

Answer 3

you do know that the derivative of a function is the slope right?

Answer 4

never mind i see it

Answer 5

so should i have y=4x-2?