Question

(Inverse) y=(1-x^1/2)/(1+x^1/2)

Answer 1

\[x=\frac{ 1-\sqrt{y} }{ 1+\sqrt{y} }\]

Answer 2

Multiply by Conject?

Answer 3

\[x=\frac{ 1-2\sqrt{y}+y }{ 1-y }\]

Answer 4

\[x=\frac{ -2\sqrt{y} + y }{ -y}\]

Answer 5

is this the right path?

Answer 6

\[x+1 = \frac{ 2\sqrt{y} }{ y }\]

Answer 7

\[y(x+1)=2\sqrt{y}\]

Answer 8

\[\frac{ y(x+1) }{ 2 } = \sqrt{y}\]

Answer 9

Is this looking right?

Answer 10

The trick to finding the inverse is to go back to the original, substitute x for y, and y for x. Your new problem would be\[x=\frac{ 1-y ^{\frac{ 1 }{ 2 }} }{ 1+x ^{\frac{ 1 }{ 2 }} }\]Now solve for y

Answer 11

would it be /1+y^(1/2)?

Answer 12

I'm sorry made a typo RHS denominator should be y to half power

Answer 13

ok

Answer 14

Would I cross multiply or is there something "simplier" to do?

Answer 15

?????
\[x(1+y ^{1/2}) = 1-y ^{1/2}\]

Answer 16

\[x+xy ^{1/2} = 1 - y ^{1/2}\]

Answer 17

It's a clever problem. You have to put the apples on one side and the oranges on the other side.

Answer 18

\[y ^{1/2} +xy ^{1/2} = 1-x\]

Answer 19

\[y ^{1/2} = \frac{ 1-x }{ 1+x }\]

Answer 20

\[y=\frac{ (1-x)^{2} }{(1+x)^{2}}\]

Answer 21

????

/Holds breath

Answer 22

Yeah, that's right, good job.

Answer 23

Wooohooo
Thank you!