Question

here is how far I've gotten
\[(x-1)y''+y'=0\]
\[y=\sum_{n=0}^{\infty} a_n x^n\]
\[y'=\sum_{n=1}^{\infty} a_n x^{n-1}\]
\[y''=\sum_{n=2}^{\infty} n(n-1)a_n x^{-2} \]
so what would this be
(x-1)y''=?

Answer 1

@satellite73 how would I write this sum?

Answer 2

@Outkast3r09 how would you write this sum?

Answer 3

you have to split each up

Answer 4

\[xy''-y''

Answer 5

xy''-y''

Answer 6

oh I see, makes sense

Answer 7

thanks!