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solve for x: x/m+n=x/n+m
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Get common denominators: xn+n^2m=xm+nm^2 Now get the x's on one side xn-xm=nm^2-n^2m Factor out x x(n-m)=nm^2-n^2m Divide by n-m x=(nm^2-n^2m)/(n-m)
i got that too. but my book says the answer is -mn?
my bad didn't see you can factor top So from: x=(nm^2-n^2m)/(n-m) x=((-nm(n-m))/(n-m)) So the (n-m) cancell x=-mn
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