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Mathematics 14 Online
OpenStudy (anonymous):

solve for x: x/m+n=x/n+m

OpenStudy (anonymous):

Get common denominators: xn+n^2m=xm+nm^2 Now get the x's on one side xn-xm=nm^2-n^2m Factor out x x(n-m)=nm^2-n^2m Divide by n-m x=(nm^2-n^2m)/(n-m)

OpenStudy (anonymous):

i got that too. but my book says the answer is -mn?

OpenStudy (anonymous):

my bad didn't see you can factor top So from: x=(nm^2-n^2m)/(n-m) x=((-nm(n-m))/(n-m)) So the (n-m) cancell x=-mn

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