Question

Find all solutions to the equation!
\[4b^{2} + 8b = 0\]
Please walk me through step by step thanks!

Answer 1

Factorize the left side by taking about b as the common factor. Put each factor =0 and solve b.

Answer 2

i am not following, mind showing me?

Answer 3

For example, if you have 2x+xy and you want to factorize it, you do it like this:
2x + xy , since x is the something common between the two terms, you take it out, and group the rest:
x (2+y)
Understand?

Answer 4

The common factor is 4b, so pull 4b out.
\[4b(b+2)=0\]
Then set each term to 0. Trying not to give away too much, sorry @Callisto is right, just trying to be more specific.

Answer 5

I will try it xD thanks guys