f(x)=7x+2 compute and simplify the difference quotient f(a+h)-f(a)/h
I kind of understand this concept, I just can't wrap my head around it.
\[\frac{7a+7h+2-7a-2}{h}=7\]
I can get that f(a+h) is 7(a+h), but I can't see how to make the other into +2-[7a+2]
the other is 7a+2 simply
I just don't get when the a and h mean I guess, so I can't see how to relate them to the 7x+2
it's like trying to understand parallel dimensions or something lol
If it's f(cat), you just replace x by cat in the equation. Take whatever in the parenthesis and replace x with it
hmmm, maybe I'm thinking about it backwards
why isn't it 7(a+h)+2-7...oh wait thats whats throwing me, the -f
so that part should be written as -(7a+2) but i don't see why the 7 is in the parenthesis this time
Just simplify the whole thing, write what you got here.
7a+7h+2-7a-2
over h
Then you have it.
Do you get it now?
yea, kinda. I think if I just keep writing it over and over I'll just know what to do and be ok
This shouldn't be hard, all you do is replace 'x' in the equation by the stuff in the parenthesis.
yea, I know, thats whats really frustrating about it haha. what about when the equation is x^2+10x-14?
I got (a+h)^2-10(a)-14
Same stuff. Replace x
No. f(a+h) and f(a) are two separate equations. You gotta replace separately.
oh ok, well, would that be right for the first half?
no
how about (a+h)^2+10(a+h)-14 -(x)^2+10(a)-14
Don't forget your parenthesis :)
oh, and it would be -(a^2+10(a)-14) not x
got it! thanks @absolutemaster, you are the master
absolutely
haha no prob ;)
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