Question

Simplify: 4x -12 divided by x^2 - 9
This is the end of my current section

Answer 1

\[\frac{ 4x-12 }{ x^2-9 }\]

\[\frac{ 4(x-3) }{ (x-3)(x+3) }\]

Answer 2

can you take it from here or want me to elaborate more?

Answer 3

i need to see the next step too

Answer 4

the (x-3) is the common value on both the numerator and denominator so this leaves us with
\[\frac{ 4 }{ (x+3)}\]

Answer 5

you can cancel the (x-3)

Answer 6

4/x+3....that was my numbers toobut wasn't for sure.... thanks

Answer 7

no problem! Anytime