Question

Hi i am studying for a precalc test tomorrow and was wondering if someone could help me with inverse functions!

Answer 1

Where are you facing problems in finding inverses?

Answer 2

ok lemme give you the equation...

Answer 3

Okay, so what you basically do is, write it this way:
y = 2x /(3x-1)

Now you goal is to bring all "x"s on one side of the equation. Can you do it?

Answer 4

um ok so you would do it 2x/(3x-1) >> 2x/(3x-1) multiplied with (3x-1) for both top and bottom? right??

Answer 5

and then on the other side you would multiply (3x-1) by y?

Answer 6

i am just really confused about this whole thing and i feel like im doing this completely wrong:x

Answer 7

Yes. you're right.
You should get something like:

y(3x-1) = 2x

Answer 8

Now solve further.

Answer 9

ok good! then it would be .... 3xy-x= 2x?

Answer 10

Yes.

Answer 11

but then how do u get it simplified from there?

Answer 12

No.

Answer 13

3xy -y = 2x

You did a little mistake.

Answer 14

oh ok! how do u get it simplified from there? so that the x's are all on one side though?

Answer 15

YES! You are a boss at this.

Answer 16

wait so u dont have to simplify it?

Answer 17

You have to make x the subject.

Answer 18

3xy-y/2= x ?

Answer 19

3xy -y = 2x

3xy - 2x = y

Take x common:

x(3y - 2) = y

FInally:

x = y/(3y-2)

Get it?P

Answer 20

oh i see! thank you so much!