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Integrate.. (tan(lnx^4))/x
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is it (lnx)^4 or ln(x^4)?
\[\int\limits \frac{ \tan(lnx ^{4} )}{ x }\]
scratch that just u substitute for 4 lnx
^ agreed
so du =4/x
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\[\int\limits\limits \frac{ \tan(4 \ln x )}{ x }dx\]\[u=4 \ln x\]\[{du \over 4} = {1 \over x}dx\]Replace 1/x dx with du/4
\[\frac{ 1 }{ 4 }\int\limits(\tan(u))\] how do i integrate tan
\[\int\limits \tan u \space du=-\ln|\cos u| + C\]courtesy of my Diff EQ book
tan(u)=sin(u)/cos(u)..if you play with that you get what ChmE got
\[\frac{ -1 }{ 4 }\ln \left| \cos(4lnx) \right|\] got it thanks guys
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yw
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