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Algebra
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Simplify and state the domain for the expression:
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\[\frac{ 5x^3+15x^2+10x }{ 3x^3- 3x }\]
Domain will be all real numbers except those that make the denominator 0, so solve 3x^3-3x=0
How would you solve that? It'd end up being 6x = 0 correct? You can't divide 6 by 0
Or would it just be 6 because that'd be 6 over 0
You would factor it 3x(x^2-1) so 3x=0 and x^2-1=0
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Alright thanks I got it.
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