The sum of 3 consecutive ODD integers is 189. What is the first integer? (Be sure to type only the first integer in the answer blank. Do not use any variables or words.)
(2x + 1) + (2x + 3) + (2x + 5) = 189 And then just solve for x first. Then your 3 numbers are (2x + 1), (2x + 3), and (2x + 5) It is written this way because by multiplying by 2 we are guaranteed to have an even number. By adding the odd numbers to each term, we have all odd numbers.
thank u :))
You're welcome!
Solve the combined inequality and select the answer that best describes the graph of the solution. -6x - 3 < 3 and 2x – 3 < 7
can u help me aut with that one too please ??
You have to solve for x for each, separately. Might as well start with the first one first: -6x - 3 < 3 You have to isolate the -6x term by itself first. To do that, you have to get the "-3" over to the right. Hint: you can add the same number to both sides of the inequality and you will preserve the inequality. Ok, take a stab at the first step. What do you add (or subtract ) to or from each side?
x<1 right ??
Well, I'll walk you through it. But pay attention because you are going to do the second equation and you can use this one as a model. -6x - 3 < 3 (-6x - 3) +3 < 3 + 3 -6x < 6 Now divide both sides by -6. When you divide or multiply by a negative, the sign changes direction. If positive, then keep the sign in the same direction. x > -1 Notice the sign change. Now you do the second one.
oh ok i got it thank u :))
You're welcome! But to finish it all off, you will be finding the INTERSECTION of the 2 solutions, that is, where they overlap. And the solution will have open circles at both ends.
|dw:1355199874678:dw|Your solution will look graphically something like that.
The bottom open line segment.
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