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1/3x(3x^2-1/3x+27x)=?
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\[\frac{ 1 }{ 3 } x(3x^2-\frac{ 1 }{ 3 } x+27x)\]Is this the question?
yes!
distribute the (1/3)x to each term inside the ( ) first
x^3-1/9x^2+9x^2
Lol.
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kirstin, thats right so far
factor out x^2 now
x^2(x-1/9+9)
group the like terms. subtract 1/9 from 9
Then that would be my final answer. Depending on what your teacher is looking for you could put the x^2 back in
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yes thank you!
@KG1234
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