Question

Conversions maybe, I am lost again.

Answer 1

An acute angle θ is in a right triangle with sin θ = . What is the value of cot θ?

Answer 2

cot θ=\[\sqrt{cosec^2 θ+1}=\sqrt{(1/\sin^2 θ)+1}\]

Answer 3

I am still lost

Answer 4

you know 1+cosec^2 θ=cot^2 θ?????????

Answer 5

ah ok, could you help me to translate that into the fraction form

Answer 6

means???????????

Answer 7

like sqrt 7 / 4

Answer 8

\[\sqrt7/4\]

Answer 9

i think you are lost because something is missing in the question

Answer 10

An acute angle θ is in a right triangle with sin θ =???? . What is the value of cot θ?

Answer 11

I am supposed to find cot theta

Answer 12

do you know what \(\sin(\theta)\) is? or do you have to answer in terms of sine?

Answer 13

sin theta=3/4

Answer 14

well now we can do it

Answer 15

you need the other side, can you find it?

Answer 16

ah ok, I guess I just needed the picture, but I think the other side is 3

Answer 17

I feel like such a noob.

Answer 18

actually you are not a noob. no one was born knowing this, you have to learn it
but what you need to learn is pythagoras, a theorem that in fact was known by the ancient babylonians around 3500 years ago

Answer 19

if you have a right triangle with legs of length \(a\) and \(b\) and hypotenuse \(h\) then
\[a^2+b^2=h^2\]
you need this for all trig, but it is not that hard to memorize
in this case we have
\(a^2+3^2=4^2\) and you need \(a\)

Answer 20

solving via
\[a^2+9=16\]
\[a^2=7\]
\[a=\sqrt{7}\]

Answer 21

now you can find anything you like
cosine
sine
tangent
cotangent
secant
cosecant

Answer 22

ah ok

Answer 23

now I think I can finish the quiz with out having to ask for answers.

Answer 24

Thank you.