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If the point P(-3/5,y) lies on the unit circle and P is in the second quadrant, what does y equal?
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positive 4/5 This is because (-3/5)^2 + (4/5)^2 = 1 AND your "y" values have to be positive when your x values are negative to be in the second quadrant.
|dw:1355245446095:dw|Because that is your second quadrant.
And the equation of your unit circle centered at the origin is: x^2 + y^2 = 1 = 1^2
So, working with the unknown: (-3/5)^2 + y^2 = 1 and then you solve for y. You get a positive and negative value, but, again, you take the positive value.
Making sense to you?
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@haleylou56 ?
yep thanks
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