If you could help, that would be GREAT! :D Question 1 What is the equation of a vertical line passing through the point (3, –5)? y = –5 x = –5 y = 3 x = 3 Question 2 Solve –2(2x – 3) = –6 x = –3 x = 6 x = 0 x = 3
2) -4x + 6 = - 6 -4x = - 12 divide both sides by - 4 x = 3
agreed
So thats the answer for the seccond one? what about the first?
Ley y = mx + b
slope m = ya - yb/xa - xb =.....
In this case, there is one point!, so
how do you get rid of the B if i have this problem -5=3x+b
that isn't right, first you need to find the slope
ooh... so do the point slope form. ?
since the slope for a vertical slope is infinite or none, there is no need for m in the equation.....
so, it becomes y = x + b
ok?
Yes, I get it now :) thank you!
just take these notes and remember them, for a vertical line, the slope is infinity or none, for a horizontal line it is 0, for any other line, use the slope formula to figure out m, which is the slope
good job
any other problems?
soo.. I think its x=-5? correct? or is it y=-5?
and yes i have more problems
ok then post them and i will help u
or you can do it this way point slope form y-y1=m(x-x1) where x1 and y1 is your point (x1,y1) we know the point is (3, –5) so x1=3 and y1=-5 and we know that a vertical line has no slope so m=0 plug that in and we have y+5=0(x-3) that right side turns into zero y+5=0 subtract 5 to both sides to get y by itself y=-5 and there you go
y = -5
thanks :D
np
Question 3 What is the equation of the line passing through (2, –2) and perpendicular to the line y = –x + 3 in slope-intercept form? y = x y = –x y = x – 4 y = x + 4 Question 4 To which graph does the point (–1, –4) belong? y < –x + 4 y < –x – 5 y < 2x – 3 y < 5x + 1 Question 5 What is the standard form equation of the line passing through (5, –3) with a slope of –3? 3x + y = 12 3x + y = –12 3x – y = 12 3x – y = –12
give me a sec
ok :)
for questions 3 all you have to do is follo my point slope form you have your x1 and y1 and now you need your slope. The slope will be a the negative reciprocal of the slope of the other function given.
for q 5: let y=mx +c, -3= -15 + c 12=c y= -3x +12, thus 3x + y = 12
p.s......i think the other guy doesn't know math, but wants to pretend to be smart, lol.....
for q 4: Y < -X + 4. You put (-1) in for X & (-4) in for Y. (-4) < -(-1) +4. -4 < 1 + 4. -4 < 5 is true. (-4) < -(-1) - 5. -4 < 1 - 5. -4 < -4 is false. -(4) < 2(-1) - 3. -4 < -2 -3. -4 < -5 is false. (-4) < 5(-1) + 1. -4 < -5 + 1. -4 < -4 is false.
for q 3, i was a bit stuck but now i got it, hold on
hahaha :P well, i suck at math too :P and thank you for helping mee :) ur the best! lol
thnxs np, hold on i almost got 3
First, put the line x+y-1=0 into the slope intercept form
ex
your equation is, already in it, my bad
Next, find the reciprocal of the slope,
-3, i think
Next, put into point slope form of the perpendicular line using the point
y + 2 = 3(x - 2)
i did this wrong hold on
ok.
i think its y = x, just by looking at it
definitely y = x
any others?
ok :D and yesss
cool
Solve 2 – 5x = x – 10 x = –3 x = –2 x = 2 x = 3 I got x=-2 is that correct?
yes
oh no
let me show u
Question 10 What is the vertex of the graph of y = |–x + 4| + 1? (5, –1) (4, 5) (4, 1) (5, 1) Question 11 Solve 3x + 2y = –12 for y. y = three-halvesx – 6 y = negative three-halvesx – 6 y = three-halvesx – 12 y = negative three-halvesx – 12
okay
2 - 5x = x - 10, -5x-x = -10-2, -6x = -12, 6x = 12, x = 2,.....ok?
oh! okayyyyy :)
I'm working on 10 and 11 now
ok
for q 10: +1 is the y value and, -x+4=0 -x=-4 -x/-1=-4/-4 =4 therefore (4,1)
ok! thats what i got as well :)
for q 11; 3x + 2y = –12, 2y = -12 - 3x, y = -3x -12/2,
well i gtget some sleep, but tell me next time your on open study, and ill help u,k?
do u know when?
Okay! sounds great! :D thank you so much for all your help! I really depreciate it :)
np, message me any more problems k? Im on here every day from 7 - 10 pm ok? ill se yah, p.s. Im from el segundo ca, where u from?
lol bye
ok, i will :) and thats cool. haha, im from Florida! lol byee ttyl
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