Question

p'=3p-p^2
just need a start. Thanks

Answer 1

what does \(p'\) represent?

Answer 2

dp/dt

Answer 3

i don't remember any of this stuff, but i think you can divide, get
\[\frac{p'}{3p-p^2}=1\] integrate both sides get \[\int\frac{p'}{3p-p^2}=t\]

Answer 4

hm i will try.thanx

Answer 5

partial fractions should do the integral

Answer 6

what i have figured so far is that p(t)=0 and p(t)=3

Answer 7

partial fractions did it! thanx:)

Answer 8

\[\frac{1}{3y-y^2}=\frac{1}{3}\left(\frac{1}{y}-\frac{1}{y-3}\right)\]

Answer 9

yw